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44x^2-19x+2=0
a = 44; b = -19; c = +2;
Δ = b2-4ac
Δ = -192-4·44·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-3}{2*44}=\frac{16}{88} =2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+3}{2*44}=\frac{22}{88} =1/4 $
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